If sin 3A = cos (A-26°), where 3A is an acute angles , find the value of A . ​

2 thoughts on “If sin 3A = cos (A-26°), where 3A is an acute angles , find the value of A . ​”

1. Answer:

   sin=cos(A-26°) where 3a is an acute

   [tex] angle6514[/tex]

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2. Given:–

   • sin 3A = cos(a − 26)
   • 3A is an acute angle.

   To Find:–

   • the value of A.

   step-by-step solution:–

   ⇒ cos(90 − 3a) = cos(a− 26)

   ⇒ (90 − 3a) = (a − 26)

   ⇒ 4a = 116°

   a = 29°

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