Molar conductance at infinite dilution of Ti(NO3)2, H2SO4 and HNO3 solution in water are a, b and c respectively. Molar conductance of TiSO4 solution at infinite dilution is a – b + c a + ab + c a + b – 2 c a – b + 2 c About the author Natalia
Given: Molar conductance at infinite dilution of Ti(NO3)2, H2SO4 and HNO3 solution in water are a, b and c respectively. To find: Molar conductance of TiSO4 solution at infinite dilution? Calculation: The molar conductance for [tex]TiSO_{4}[/tex] can be written as : [tex] \rm(\land_{\infty}^{\circ})_{TiSO_{4}} = (\land_{\infty}^{\circ})_{Ti(NO_{3})_{2}} + (\land_{\infty}^{\circ})_{H_{2}SO_{4}} – 2 (\land_{\infty}^{\circ})_{HNO_{3}}[/tex] [tex] \rm \implies (\land_{\infty}^{\circ})_{TiSO_{4}} = a + b – 2c[/tex] So, the final answer is: [tex] \boxed{ \bf(\land_{\infty}^{\circ})_{TiSO_{4}} = a + b – 2c}[/tex] The usefulness of this method is that: It can be used to calculate the molar conductivity for a compound with the values of related compounds. Hope It Helps. Reply
Given:
Molar conductance at infinite dilution of Ti(NO3)2, H2SO4 and HNO3 solution in water are a, b and c respectively.
To find:
Molar conductance of TiSO4 solution at infinite dilution?
Calculation:
The molar conductance for [tex]TiSO_{4}[/tex] can be written as :
[tex] \rm(\land_{\infty}^{\circ})_{TiSO_{4}} = (\land_{\infty}^{\circ})_{Ti(NO_{3})_{2}} + (\land_{\infty}^{\circ})_{H_{2}SO_{4}} – 2 (\land_{\infty}^{\circ})_{HNO_{3}}[/tex]
[tex] \rm \implies (\land_{\infty}^{\circ})_{TiSO_{4}} = a + b – 2c[/tex]
So, the final answer is:
[tex] \boxed{ \bf(\land_{\infty}^{\circ})_{TiSO_{4}} = a + b – 2c}[/tex]
Hope It Helps.