URGENT HELP NEEDED FROM AN EXPERT Q1 The position ‘x’ of the particle varies with time as x= at^2- b^3.Calculate the acceleration after two seconds About the author Kylie
Answer: x=at 2 −bt 3 ⇒ Velocity = dt dx =2at−3bt 2 Acceleration= dt 2 d 2 x = dt d (2at−3b 2 )=2a−6bt or a=2a−6bt Making a=0 ⇒2a=6bt ⇒t=dfrac2a6b= 3b a . Reply
Answer:
x=at
2
−bt
3
⇒ Velocity =
dt
dx
=2at−3bt
2
Acceleration=
dt
2
d
2
x
=
dt
d
(2at−3b
2
)=2a−6bt
or a=2a−6bt
Making a=0
⇒2a=6bt
⇒t=dfrac2a6b=
3b
a
.