2 tables and 3 chairs together cost Rs. 2000 whereas 3 tables and 2 chairs together cost Rs. 2500.Find the total cost of 1 table and 5 chairs solving the equations graphically. About the author Savannah
Given : • 2 tables and 3 chairs together cost Rs. 2000 whereas 3 tables and 2 chairs together cost Rs 2500 To Find : • The cost of 1 table and 5 chairs. Solution : According to the question, Let, The cost of 1 table and 1 chair be x & y. 2x + 3y = 2000 …(i) 3x + 2y = 2500 …(ii) From equation (i), 2x + 3y = 2000 x = 2000 – 3y/2 Putting the value of x in equation (ii) → 3x + 2y = 2500 → 3(2000 – 3y/2) + 2y = 2500 → 6000 – 9y/2+ 2y = 2500 → 6000 – 9y + 4y = 2500 × 2 → 6000 – 5y = 5000 → -5y = 5000 – 6000 → -5y = – 1000 → y = 200 Substituting the value of x in equation (i) → 2x + 3y = 2000 → 2x + 3(200) = 2000 → 2x + 600 = 2000 → 2x = 1400 → x = 700 So, the cost of 1 table is Rs 700 and the cost of 5 chair is 5 × 200 = Rs 1000 Reply
Given :
• 2 tables and 3 chairs together cost Rs. 2000 whereas 3 tables and 2 chairs together cost Rs 2500
To Find :
• The cost of 1 table and 5 chairs.
Solution :
According to the question,
Let,
2x + 3y = 2000 …(i)
3x + 2y = 2500 …(ii)
From equation (i),
2x + 3y = 2000
x = 2000 – 3y/2
Putting the value of x in equation (ii)
→ 3x + 2y = 2500
→ 3(2000 – 3y/2) + 2y = 2500
→ 6000 – 9y/2+ 2y = 2500
→ 6000 – 9y + 4y = 2500 × 2
→ 6000 – 5y = 5000
→ -5y = 5000 – 6000
→ -5y = – 1000
→ y = 200
Substituting the value of x in equation (i)
→ 2x + 3y = 2000
→ 2x + 3(200) = 2000
→ 2x + 600 = 2000
→ 2x = 1400
→ x = 700
So, the cost of 1 table is Rs 700
and the cost of 5 chair is 5 × 200 = Rs 1000