[tex]x {}^{2} + 3x {}^{2} + 3x + 1 \div x – \frac{1}{2} [/tex]
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1 thought on “<br />[tex]x {}^{2} + 3x {}^{2} + 3x + 1 \div x – \frac{1}{2} [/tex]<br />​”

1. Step-by-step explanation:

   x

   2

   +3x+1=(x−2)

   2

   x

   2

   +3x+1=x

   2

   −4x+4

   ⇒x

   2

   +3x+1−x

   2

   +4x−4=0

   ⇒7x−3=0 has its highest power 1

   Hence it is not a quadratic equation

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