5 is one of the zero of the polynomial of P(x)= x3+9x2423x+15.​

2 thoughts on “5 is one of the zero of the polynomial of P(x)= x3+9x2423x+15.​”

1. Answer:

   Given that,

   p(x)=5x

   2

   +13x−a

   Here, a=5,b=13 & c=−a

   Let, the zeroes are α,

   α

   1

   Product of zeroes (α×

   α

   1

   )=

   a

   c

   ⟹1=

   5

   −a

   ⟹5=−a

   ∴a=−5

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2. Hope It’s Help U !!

   a = –5

   have A SwEeT Day

   Reply