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Find the value of p, If the equation
3x^2+2x+p=0 and 6x^2-17x+12=0
Explain why we get double answer.​

By Everleigh

Find the value of p, If the equation
3x^2+2x+p=0 and 6x^2-17x+12=0
Explain why we get double answer.​

About the author
Everleigh

1
(C)
1 2 5 7
1 2 4 3
2. Arrange in ascending order: (a)
(b)
33′ 69
2′ 3′ 5′ 4
7 5 13 11 3

Evaluate:
[tex]4 \sqrt{3} – 3 \sqrt{12} + \sqrt{75} \: if \: \sqrt{3} = 1.732[/tex]

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1 thought on “Find the value of p, If the equation<br />3x^2+2x+p=0 and 6x^2-17x+12=0<br />Explain why we get double answer.​”

  1. Step-by-step explanation:

    6x²-17x+12=0

    =6x²-9x-8x+12=0

    =3x(2x-3) -4(2x-3) =0

    =(3x-4) (2x-3) =0

    • when 3x-4=0

    3x=4

    x=4/3

    • when 2x-3=0

    2x=3

    x=3/2

    NOW IN Equation 1

    • 3x²+2x+p=0

    WE HAVE TWO VALUE OF X

    SO WE GET TWO DIFFERENT ANSWER AFTER PUTTING THE VALUE

    Reply

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