In a ∆ abc,ab = ac and < b = 45° then find the value of < a, < c.

2 thoughts on “In a ∆ abc,ab = ac and < b = 45° then find the value of < a, < c.”

1. In a triangle abc,

   ab= ac (given)

   and <b= 45°

   so, <c= 45° ( if the sides of a triangle are equal then their angles are also equal)

   now,

   <a + <b + <c =180° ( angle sum property)

   <a + 45° + 45° = 180°

   <a + 90° = 180°

   <a = 180°- 90°

   <a = 90°

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2. Answer:

   < a = 90° , < c = 90 °

   It is an isosceles traingle so its opposite angles are always equal angle = 45°

   According to angle some property a+b+c = 180°

   a+45+45 = 180°

   a = 180-90

   a = 90°

   AB = AC..

   Step-by-step explanation:

   ____________________

   Here is your answer dear, hope it will helps you...

   Have a great day ahead..

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