Q.3) Fill in the blanks:(1 markt(1) ABC is an equilateral triangle of side a. Its area will be(ii) The distance of the point (a, b) from the origin is About the author Hadley
Answer 1. √3/2 * (a^2) sq. units ii. √a^2 + b^2 units Step-by-step explanation: 1. All the sides are equal. so by Herons formula S = (a + a + a )/2 = 3a/2 area = √s(s-a)(s-b)(s-c) sq. units here √3a/2(3a/2-a)(3a/2-a)(3a/2- a) =√(3a/2)(a/2)(a/2)(a/2) =√3a⁴/16 = √3/2 * (a²) sq. units 2. Formula to find distance between two points is √(X2 – X1)²+ (y2 -y1)² origin (0,0) and (a,b) here X1 =0 y1 = 0 X2 =a y2 = b then we have √(a – 0)² +(b – 0)² √a² + b² units. Reply
Answer:
Step-by-step explanation:
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Answer 1. √3/2 * (a^2) sq. units
ii. √a^2 + b^2 units
Step-by-step explanation:
1. All the sides are equal. so by Herons formula
S = (a + a + a )/2 = 3a/2
area = √s(s-a)(s-b)(s-c) sq. units
here √3a/2(3a/2-a)(3a/2-a)(3a/2- a)
=√(3a/2)(a/2)(a/2)(a/2)
=√3a⁴/16
= √3/2 * (a²) sq. units
2. Formula to find distance between two points is √(X2 – X1)²+ (y2 -y1)²
origin (0,0) and (a,b)
here X1 =0 y1 = 0
X2 =a y2 = b
then we have √(a – 0)² +(b – 0)²
√a² + b² units.