Answer: [tex]10 {p}^{2} q + 5 p{q}^{2} – 2pq + 14 – ( – 12pq + 2 {p}^{2} q – 6pq^{2} ) \\ = 10 {p}^{2} q + 5 p{q}^{2} – 2pq + 14 + 12pq – 2 {p}^{2} q + 6pq^{2} ) \\ = 8{p}^{2} q + 11p{q}^{2} + 10pq + 14[/tex] Reply
Answer:
[tex]10 {p}^{2} q + 5 p{q}^{2} – 2pq + 14 – ( – 12pq + 2 {p}^{2} q – 6pq^{2} ) \\ = 10 {p}^{2} q + 5 p{q}^{2} – 2pq + 14 + 12pq – 2 {p}^{2} q + 6pq^{2} ) \\ = 8{p}^{2} q + 11p{q}^{2} + 10pq + 14[/tex]