The age of two persons are now the ratio 9:2,The sum of their present ages is 55. Find their present ages. About the author Adalynn
Given : The Present age of two persons are now the ratio 9:2 & sum of their present ages is 55. Need To Find : Their Present ages . ❍ Let’s Consider their ages be 9x yrs and 2x yrs . Given that, The sum of their present ages is 55. Therefore, [tex]\bf{\star \underline {Equation = 9x + 2x = 55}}\\[/tex] ⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Solving\:for\:x\:in \: the \: Formed \: Equation ::}}\\[/tex] [tex] \qquad:\implies \sf{Equation = 9x + 2x = 55}\\[/tex] [tex] \qquad:\implies \sf{ 9x + 2x = 55}\\[/tex] [tex] \qquad:\implies \sf{ 11x = 55}\\[/tex] [tex] \qquad:\implies \sf{x = \cancel {\dfrac{55}{11}}}\\[/tex] ⠀⠀⠀⠀⠀[tex]\underline {\boxed{\pink{ \mathrm { x = 5\:yrs }}}}\:\bf{\bigstar}\\[/tex] Therefore, The Present age of First Person is 9x = 9 × 5 = 45 yrs . The Present age of Second Person is 2x = 2 × 5 = 10 yrs. Therefore, ⠀⠀⠀⠀⠀[tex]\therefore {\underline{ \mathrm { Hence\:Their\:Present \:ages\:area \:\bf{45\:yrs\:\&\:10yrs\: }}}}\\[/tex] ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ V E R I F I C A T I O N : As , We know that , [tex]\bf{\star \underline {Equation = 9x + 2x = 55}}\\[/tex] Where , [tex] \qquad:\implies \sf{ x = 5}\\[/tex] ⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\[/tex] [tex] \qquad:\implies \sf{ 9 \times 5 + 2 \times 5 = 55}\\[/tex] [tex] \qquad:\implies \sf{ 45 + 2 \times 5 = 55}\\[/tex] [tex] \qquad:\implies \sf{ 45 + 10 = 55}\\[/tex] [tex] \qquad:\implies \sf{ 55 = 55}\\[/tex] ⠀⠀⠀⠀⠀[tex]\therefore {\underline {\bf{ Hence, \:Verified \:}}}\\[/tex] ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ Reply
Answer :– The present ages of the persons are 45 years and 10 years. Given :– The age of two persons are in the ratio 9 : 2. The sum of their present ages is 55. To find :– Their present ages. Step-by-step explanation :– The present ages of two persons are in the ratio 9 : 2. So, let their ages be 9x and 2x. Now, [tex] \mathfrak{It \: has \: been \: given \: that,} [/tex] The sum of their ages is 55. So, that means the sum of 9x and 2x is equal to 55. Therefore, let’s use this information to form an equation and solve it to find out our answer. [tex] \boxed{\sf \implies 9x + 2x = 55}[/tex] Adding 9x and 2x, [tex] \boxed{\sf \implies 11x = 55}[/tex] Transposing 11 from LHS to RHS, changing it’s sign, [tex] \boxed{\sf \implies x = \dfrac{55}{11}} [/tex] Dividing 55 by 11, [tex] \overline{\boxed{ \sf \implies x = 5.}}[/tex] The value of x = 5. –––––––––––––––––––––––––––– Hence, the present ages of the persons are as follows :– [tex] \tt 9x = 9 \times 5 = 45.[/tex] [tex] \tt2x = 2 \times 5 = 10.[/tex] ———————————————————– Verification :– To verify our answer, we just have to put 5 (The value of x) in the place of x and see whether LHS = RHS. Let’s do it! Substituting the value of x in the given equation, LHS [tex] \Rightarrow \sf 9 \times 5 + 2 \times 5 [/tex] On simplifying, [tex] \Rightarrow \sf 45 + 10 [/tex] Adding 10 to 45, [tex] \Rightarrow \sf 55 [/tex] RHS [tex] \Rightarrow \sf 55 [/tex] Since LHS = RHS, Hence verified! Reply
Given : The Present age of two persons are now the ratio 9:2 & sum of their present ages is 55.
Need To Find : Their Present ages .
❍ Let’s Consider their ages be 9x yrs and 2x yrs .
Given that,
Therefore,
⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Solving\:for\:x\:in \: the \: Formed \: Equation ::}}\\[/tex]
[tex] \qquad:\implies \sf{Equation = 9x + 2x = 55}\\[/tex]
[tex] \qquad:\implies \sf{ 9x + 2x = 55}\\[/tex]
[tex] \qquad:\implies \sf{ 11x = 55}\\[/tex]
[tex] \qquad:\implies \sf{x = \cancel {\dfrac{55}{11}}}\\[/tex]
⠀⠀⠀⠀⠀[tex]\underline {\boxed{\pink{ \mathrm { x = 5\:yrs }}}}\:\bf{\bigstar}\\[/tex]
Therefore,
Therefore,
⠀⠀⠀⠀⠀[tex]\therefore {\underline{ \mathrm { Hence\:Their\:Present \:ages\:area \:\bf{45\:yrs\:\&\:10yrs\: }}}}\\[/tex]
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
V E R I F I C A T I O N :
As , We know that ,
Where ,
⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}\\[/tex]
[tex] \qquad:\implies \sf{ 9 \times 5 + 2 \times 5 = 55}\\[/tex]
[tex] \qquad:\implies \sf{ 45 + 2 \times 5 = 55}\\[/tex]
[tex] \qquad:\implies \sf{ 45 + 10 = 55}\\[/tex]
[tex] \qquad:\implies \sf{ 55 = 55}\\[/tex]
⠀⠀⠀⠀⠀[tex]\therefore {\underline {\bf{ Hence, \:Verified \:}}}\\[/tex]
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
Answer :–
Given :–
To find :–
Step-by-step explanation :–
Now,
[tex] \mathfrak{It \: has \: been \: given \: that,} [/tex]
[tex] \boxed{\sf \implies 9x + 2x = 55}[/tex]
Adding 9x and 2x,
[tex] \boxed{\sf \implies 11x = 55}[/tex]
Transposing 11 from LHS to RHS, changing it’s sign,
[tex] \boxed{\sf \implies x = \dfrac{55}{11}} [/tex]
Dividing 55 by 11,
[tex] \overline{\boxed{ \sf \implies x = 5.}}[/tex]
––––––––––––––––––––––––––––
Hence, the present ages of the persons are as follows :–
[tex] \tt 9x = 9 \times 5 = 45.[/tex]
[tex] \tt2x = 2 \times 5 = 10.[/tex]
———————————————————–
Verification :–
To verify our answer, we just have to put 5 (The value of x) in the place of x and see whether LHS = RHS.
Let’s do it!
Substituting the value of x in the given equation,
LHS
[tex] \Rightarrow \sf 9 \times 5 + 2 \times 5 [/tex]
On simplifying,
[tex] \Rightarrow \sf 45 + 10 [/tex]
Adding 10 to 45,
[tex] \Rightarrow \sf 55 [/tex]
RHS
[tex] \Rightarrow \sf 55 [/tex]
Since LHS = RHS,
Hence verified!