Eight years ago, the ratio of the ages of Samir and Varun was 4:3. Eight years hence, the ratio of their ag6:5. What is the sum of their present ages? About the author Peyton
GIVEN :- Eight years ago, the ratio of the ages of Samir and Varun was 4:3. Eight years hence, the ratio of their age 6:5. [tex] \\ [/tex] TO FIND :- Sum of their present ages. [tex] \\ [/tex] SOLUTION :- Let present age of Samir be ‘x’yrs and Varun be ‘y’yrs. CASE 1 — Eight years ago, the ratio of the ages of Samir and Varun was 4:3. Eight years ago, Age of Samir → ‘x – 8’ yrs Age of Varun → ‘y – 8’ yrs Ratio was 4:3. [tex] \\ \sf \: \dfrac{x – 8}{y – 8} = \dfrac{4}{3} \\ \\ \sf \: 3(x – 8) = 4(y – 8) \\ \\ \sf \: 3x – 24 = 4y – 32 \\ \\ \sf \: 3x – 4y = – 32 + 24 \\ \\ \sf \: 3x – 4y = – 8 \\ [/tex] Multiplying whole equation by 5, [tex] \\ \sf \: 15x – 20y = – 40 \: \: \: \: \: \: \: – – – (1) \\ \\ [/tex] CASE 2— Eight years hence, the ratio of their age 6:5. Eight years hence , Age of Samir → ‘x + 8’ yrs Age of Varun → ‘y + 8’ yrs Ratio will be 6:5. [tex] \\ \sf \: \dfrac{x + 8}{y + 8} = \dfrac{6}{5} \\ \\ \sf \: 5(x + 8) = 6(y + 8) \\ \\ \sf \: 5x + 40 = 6y + 48 \\ \\ \sf \: 5x – 6y = 48 – 40 \\ \\ \sf \: 5x – 6y = 8 \\ [/tex] Multiplying whole equation by 3, [tex] \\ \sf \: 15x – 18y = 24 \: \: \: \: \: \: \: – – – (3) \\ \\ [/tex] Subtracting equation (2) by equation (1) , → 15x – 20y – (15x – 18y) = -40 – (24) → 15x – 20y – 15x + 18y = -40 – 24 → -2y = -64 → y = -64/-2 → y = 32 Putting y=32 in equation (3) , → 15x – 18(32) = 24 → 15x – 576 = 24 → 15x = 24 + 576 → 15x = 600 → x = 600/15 → x = 40 Hence , age of Samir is 40 years and age of Varun is 32years. Sum of their ages = 40 + 32 = 72years. Hence , sum of the ages of Samir and Varun is 72 years. Reply
GIVEN :-
[tex] \\ [/tex]
TO FIND :-
[tex] \\ [/tex]
SOLUTION :-
Let present age of Samir be ‘x’yrs and Varun be ‘y’yrs.
CASE 1 —
Eight years ago, the ratio of the ages of Samir and Varun was 4:3.
Eight years ago,
[tex] \\ \sf \: \dfrac{x – 8}{y – 8} = \dfrac{4}{3} \\ \\ \sf \: 3(x – 8) = 4(y – 8) \\ \\ \sf \: 3x – 24 = 4y – 32 \\ \\ \sf \: 3x – 4y = – 32 + 24 \\ \\ \sf \: 3x – 4y = – 8 \\ [/tex]
Multiplying whole equation by 5,
[tex] \\ \sf \: 15x – 20y = – 40 \: \: \: \: \: \: \: – – – (1) \\ \\ [/tex]
CASE 2—
Eight years hence, the ratio of their age 6:5.
Eight years hence ,
[tex] \\ \sf \: \dfrac{x + 8}{y + 8} = \dfrac{6}{5} \\ \\ \sf \: 5(x + 8) = 6(y + 8) \\ \\ \sf \: 5x + 40 = 6y + 48 \\ \\ \sf \: 5x – 6y = 48 – 40 \\ \\ \sf \: 5x – 6y = 8 \\ [/tex]
Multiplying whole equation by 3,
[tex] \\ \sf \: 15x – 18y = 24 \: \: \: \: \: \: \: – – – (3) \\ \\ [/tex]
Subtracting equation (2) by equation (1) ,
→ 15x – 20y – (15x – 18y) = -40 – (24)
→ 15x – 20y – 15x + 18y = -40 – 24
→ -2y = -64
→ y = -64/-2
→ y = 32
Putting y=32 in equation (3) ,
→ 15x – 18(32) = 24
→ 15x – 576 = 24
→ 15x = 24 + 576
→ 15x = 600
→ x = 600/15
→ x = 40
Hence , age of Samir is 40 years and age of Varun is 32years.
Sum of their ages = 40 + 32 = 72years.
Hence , sum of the ages of Samir and Varun is 72 years.