The Fourier sine transform of f(t)=1 for 0<t<1 is

The Fourier sine transform of f(t)=1 for 0<t<1 is

About the author
Abigail

1 thought on “The Fourier sine transform of f(t)=1 for 0<t<1 is<br />​”

  1. Step-by-step explanation:

    Step-by-step explanation:What is the Fourier sine and cosine transform of f(x)=1f(x)=1? I have seen some sources refer to the transform of f=1f=1 involving the Dirac Delta function, but this goes against the integral definition for the Fourier sine transform, for example, since

    Step-by-step explanation:What is the Fourier sine and cosine transform of f(x)=1f(x)=1? I have seen some sources refer to the transform of f=1f=1 involving the Dirac Delta function, but this goes against the integral definition for the Fourier sine transform, for example, since∫∞0f(x)sin(xt)dx,

    Step-by-step explanation:What is the Fourier sine and cosine transform of f(x)=1f(x)=1? I have seen some sources refer to the transform of f=1f=1 involving the Dirac Delta function, but this goes against the integral definition for the Fourier sine transform, for example, since∫∞0f(x)sin(xt)dx,∫0∞f(x)sin⁡(xt)dx,

    Step-by-step explanation:What is the Fourier sine and cosine transform of f(x)=1f(x)=1? I have seen some sources refer to the transform of f=1f=1 involving the Dirac Delta function, but this goes against the integral definition for the Fourier sine transform, for example, since∫∞0f(x)sin(xt)dx,∫0∞f(x)sin⁡(xt)dx,diverges when f=1f=1 doesn’t it?

    Reply

Leave a Comment