The general solution of p – 1 = 0 is
ans.
po-=c
y²- 2yc + x² + ² = 0
y²– 2yc – x² + c² = 0
y² – 2xy + x²

1 thought on “The general solution of p – 1 = 0 is<br />ans.<br />po-=c<br />y²- 2yc + x² + ² = 0<br />y²– 2yc – x² + c² = 0<br />y² – 2xy + x²”

1. Answer:

   ph ²– 2yc – x² + c² = 0

   y² – 2xy + x² + c² = 0

   x2_-xy!

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