PA and PB are the tangents drawn to circle from external point P .PA = 6cm ,QR is another tangents touch the circle at S and intersect PA at Q and PB at R .The perimeter of triangle PQR is About the author Lyla
Step-by-step explanation: Correct option is A 20 From the graph, we find some conclusion- PA=PB=10cm CE=CA DE=DB Perimeter of ΔPCD is, =PC+PD+CD ⇒PC+PD+CE+ED ⇒PC+PD+CA+DB ⇒(PC+CA)(PD+DB) ⇒PA+PB ⇒10+10 ⇒20 cm.  Reply
Step-by-step explanation:
Correct option is
A
20
From the graph, we find some conclusion-
PA=PB=10cm
CE=CA
DE=DB
Perimeter of ΔPCD is,
=PC+PD+CD
⇒PC+PD+CE+ED
⇒PC+PD+CA+DB
⇒(PC+CA)(PD+DB)
⇒PA+PB
⇒10+10
⇒20 cm.