A wire of 160cm is bent to form a square, find its side.
23)​

2 thoughts on “<br />A wire of 160cm is bent to form a square, find its side.<br />23)​”

1. Given:

   • Length of the wire = 160 cm
   • The wire is bent to form a square.

   [tex] \: [/tex]

   To find:

   • Side of the square.

   [tex] \: [/tex]

   Solution:

   As the wire of 160 cm is bent to form a square, then the perimeter of the square is equal to the length of the wire.

   That is,

   Perimeter of square = Length of wire

   [tex]\boxed {\mathfrak {\purple {Perimeter\ of\ square = 160\ cm}}}[/tex]

   Now, as we know that,

   Perimeter of square = 4×side

   160 cm = 4s

   [tex]\sf {\dfrac {160}{4}}[/tex] = s

   [tex]\boxed {\bf {\red {40\ cm = side}}}[/tex]

   [tex] \: [/tex]

   Side of square:

   Side of the square whose perimeter is 160 cm is [tex]\underline {\sf {\pink {40\ cm}}}[/tex]

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2. Step-by-step explanation:

   perimeter of square is 160 cm so

   160=4( side )

   160/4 = side

   40 cm is the side of the square

   pls mark as brainliests

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