a chord of length 16 cm is drawn in a circle of a diameter 20 cm Calculate it’s distance from the centre of the circle About the author Savannah
Answer: Centre =O Chord=AB Length of Chord=16cm Radius of circle =20/2=10cm(OA) Draw a perpendicular on Chord Chord divided two equal parts AM and MB(16/2=8) In triangle ;OAM is a Right angle triagle. By pythagorouse theorem; OA^2=AM^2+OM^2 (10)^2=8^2+(OM)^2 100-64=OM^2 36=(OM)^2 6^2=(OM)^2 OM=6cm distance from the centre of the circle =6cm Reply
Answer:
Centre =O
Chord=AB
Length of Chord=16cm
Radius of circle =20/2=10cm(OA)
Draw a perpendicular on Chord
Chord divided two equal parts
AM and MB(16/2=8)
In triangle ;OAM is a Right angle triagle.
By pythagorouse theorem;
OA^2=AM^2+OM^2
(10)^2=8^2+(OM)^2
100-64=OM^2
36=(OM)^2
6^2=(OM)^2
OM=6cm
distance from the centre of the circle =6cm
Answer:
10 cm because radius is half of diameter