the side of rectangle are in the ratio 3:5 what is the length of it’s side if the perimeter is 64cm About the author Julia
Answer: 4 Step-by-step explanation: L = 3x B = 5x [tex]perimeter \: of \: rectngle \: = 2(l + b) \\ 64 = 2(l + b) \\ 64 = 2(3x + 5x) \\ 64 = 2(8x) \\ 64 = 16x \\ x = \frac{64 }{16} \\ x = \frac{8 }{2} \\ x = 4[/tex] Reply
Step-by-step explanation: take 3=3x and 5=5x perimeter=2×(L+B) 64=2×(3x+5x) 64=2×8x 64=16x x=4cm 1st side =3×4=12cm 2nd side=5×4=20cm Reply
Answer:
4
Step-by-step explanation:
L = 3x
B = 5x
[tex]perimeter \: of \: rectngle \: = 2(l + b) \\ 64 = 2(l + b) \\ 64 = 2(3x + 5x) \\ 64 = 2(8x) \\ 64 = 16x \\ x = \frac{64 }{16} \\ x = \frac{8 }{2} \\ x = 4[/tex]
Step-by-step explanation:
take 3=3x
and 5=5x
perimeter=2×(L+B)
64=2×(3x+5x)
64=2×8x
64=16x
x=4cm
1st side =3×4=12cm
2nd side=5×4=20cm