Answer:83667 Step-by-step explanation: Here first term, a = 3 Second term = 9 Common difference, d = 6 Last term an = 999 a+(n-1)d = 999 3+(n-1)6 = 999 -3+6n = 999 6n = 999+3 = 1002 n = 1002/6 = 167 Sum of n terms = (n/2)(a+an) = (167/2)(3+999) = 83667 Reply
Answer:83667
Step-by-step explanation:
Here first term, a = 3
Second term = 9
Common difference, d = 6
Last term an = 999
a+(n-1)d = 999
3+(n-1)6 = 999
-3+6n = 999
6n = 999+3 = 1002
n = 1002/6 = 167
Sum of n terms = (n/2)(a+an)
= (167/2)(3+999)
= 83667
Answer:
The answer is the number : 83667