Answer: In the given figure, let CE=CF=x It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore, AF=AD=10−x BE=BD=8−x Now consider, AB=AD+BD ⇒12=10−x+8−x ⇒12=18−2x ⇒2x=18−12 ⇒2x=6 ⇒x= 2 6 =3 Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm Hence, CE=3 cm, AF=7 cm and BD=5 cm. AND PLACE TAP TO BRILLIANT ANSWER PLEASE Reply
Answer:
In the given figure, let CE=CF=x
It is also given that AB=12 cm, BC=8 cm and AC=10 cm, therefore,
AF=AD=10−x
BE=BD=8−x
Now consider,
AB=AD+BD
⇒12=10−x+8−x
⇒12=18−2x
⇒2x=18−12
⇒2x=6
⇒x=
2
6
=3
Therefore, CE=x=3 cm, AF=10−3=7 cm and BD=8−3=5 cm
Hence, CE=3 cm, AF=7 cm and BD=5 cm.
AND PLACE TAP TO BRILLIANT ANSWER PLEASE