In Fig. 11.16, P is a point in the interior of a
parallelogram ABCD Show that
0 (APB) + ar (PCD) (ABCD)
(1) (APD) .

In Fig. 11.16, P is a point in the interior of a
parallelogram ABCD Show that
0 (APB) + ar (PCD) (ABCD)
(1) (APD) .ar (PBC) – ar (APB) + ar (PCD)
(Hint: Through P. draw a line parallel to AB.]
Fig. 11.16​

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1 thought on “In Fig. 11.16, P is a point in the interior of a<br />parallelogram ABCD Show that<br />0 (APB) + ar (PCD) (ABCD)<br />(1) (APD) .”

  1. Answer:

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