Q-2: If A SQR=AXYZ, then write the parts of AXYZ that correspond to:() S (ii) SR (iii) ZR (iv) 20EZENTARAR About the author Ella
Answer: FIRST MACK THIS ANSWER BRANLYS ANSWER AND ONE THINKS PLEASE \underline{\bold{Hey\:Mate\:Here\:Is\:Your\:Answer\:}}HeyMateHereIsYourAnswer \underline{\bold{Given\:That….}}GivenThat…. ∆ABC ~ ∆PQR(Let ~ this be the Symbol Of Congruent ) And Now We Need To Find all Corresponding Angles of The Two Triangle And We Need To Also Find All Ratio Of all Corresponding Sides Now Let’s Move For Solution… \underline{\bold{Solution..}}Solution.. Now According To Question It’s Said That … ∆ABC ~ ∆PQR \underline{\bold{Note-}}Note− When It’s Given That A Triangle Is Congruent With Another Triangle Then The Corresponding Angles And Sides Would Be also In The Form OF Given Order . Example- Let … ∆EFG ~ ∆XYZ So Here EFG & XYZ Are Congruent Therefore The Corresponding Angles Would Be .. < EFG & <XYZ , <FGE & < YZX < GEF & <ZXY Therefore This All Where The Corresponding Angles.. Now It’s Corresponding Sides Are … EF & XY FG & YZ GE & ZX Hence This All Where The Corresponding Sides And Angles … Now In Question It’s Given That ∆ABC ~ ∆PQR … Therefore It’s Corresponding Angles Would Be <ABC & < PQR , <BCA & <QRA, <CAB & <RPQ Hence, This All Are The Corresponding Angles Of ∆ ABC & ∆ PQR .. Now It’s Corresponding Sides Are … AB & PQ , BC & QR, CA & RP Now By Theorem oF C.P.C.T Are Equal That Is Corresponding Parts Of Congruent Triangles Are Equal.. Therefore Here AB = PQ BC = QR CA = RP As This Sides Are Equal So Their Ration Would Be \boxed{\bold{ 1\: : \: 1 }}1:1 \boxed{\boxed{\bold{Thanks}}}Thanks Reply
Answer:
FIRST MACK THIS ANSWER BRANLYS ANSWER AND ONE THINKS PLEASE
\underline{\bold{Hey\:Mate\:Here\:Is\:Your\:Answer\:}}HeyMateHereIsYourAnswer
\underline{\bold{Given\:That….}}GivenThat….
∆ABC ~ ∆PQR(Let ~ this be the Symbol Of Congruent ) And Now We Need To Find all Corresponding Angles
of The Two Triangle And We Need To Also Find All Ratio Of all Corresponding Sides
Now Let’s Move For Solution…
\underline{\bold{Solution..}}Solution..
Now According To Question It’s Said That …
∆ABC ~ ∆PQR
\underline{\bold{Note-}}Note− When It’s Given That A Triangle Is Congruent With Another Triangle Then
The Corresponding Angles And Sides Would Be also In The Form OF Given Order .
Example-
Let …
∆EFG ~ ∆XYZ So Here EFG & XYZ Are Congruent Therefore The Corresponding Angles Would Be ..
< EFG & <XYZ ,
<FGE & < YZX
< GEF & <ZXY
Therefore This All Where The Corresponding Angles.. Now It’s Corresponding Sides Are …
EF & XY
FG & YZ
GE & ZX
Hence This All Where The Corresponding Sides And Angles …
Now In Question It’s Given That ∆ABC ~ ∆PQR …
Therefore It’s Corresponding Angles Would Be
<ABC & < PQR ,
<BCA & <QRA,
<CAB & <RPQ
Hence, This All Are The Corresponding Angles Of ∆ ABC & ∆ PQR ..
Now It’s Corresponding Sides Are …
AB & PQ ,
BC & QR,
CA & RP
Now By Theorem oF C.P.C.T Are Equal That Is Corresponding Parts Of Congruent Triangles Are Equal..
Therefore Here
AB = PQ
BC = QR
CA = RP
As This Sides Are Equal So Their Ration Would Be
\boxed{\bold{ 1\: : \: 1 }}1:1
\boxed{\boxed{\bold{Thanks}}}Thanks