Answer: No it is not a quadratic equation Step-by-step explanation: Given, [tex](12x + 13) \times {x}^{2} = 3 {x}^{2} – 5x \\ 12 {x}^{3} + 13 {x}^{2} = 3 {x}^{2} – 5x \\ 12 {x}^{3} + 13 {x}^{2} – 3 {x}^{2} + 5x = 0 \\ 12 {x}^{3} + 10 {x}^{2} + 5x = 0[/tex] We get the equation 12x³+10x²+5x=0 Comparing with ax²+by+c=0, we have 12x³ which makes the whole equation a cubic equation, hence proved. Reply
Answer:
No it is not a quadratic equation
Step-by-step explanation:
Given,
[tex](12x + 13) \times {x}^{2} = 3 {x}^{2} – 5x \\ 12 {x}^{3} + 13 {x}^{2} = 3 {x}^{2} – 5x \\ 12 {x}^{3} + 13 {x}^{2} – 3 {x}^{2} + 5x = 0 \\ 12 {x}^{3} + 10 {x}^{2} + 5x = 0[/tex]
We get the equation 12x³+10x²+5x=0
Comparing with ax²+by+c=0,
we have 12x³ which makes the whole equation a cubic equation, hence proved.