a=x, b=x+1 , c=2x-1. Area =x√10

. find x and length of all sides of triangle​

1 thought on “a=x, b=x+1 , c=2x-1. Area =x√10<br /><br />. find x and length of all sides of triangle​”

1. Answer:

   Here

   s=(x+x+1+2x-1)/2

   =4x/2

   =2x

   Now Area=√[s(s-x){s-(x+1)}{s-(2x-1)}]

   =√[2x(2x-x){2x-(x+1)}{2x-(2x-1)}]

   =√[2x^2(2x-x-1)(2x-2x+1)]

   =√[2x^2(x-1)×1]

   =√(2x^3–2x^2)

   According to question

   √(2x^3–2x^2)=x√10

   Or, {√(2x^3–2x^2)}^2={x√10}^2

   Or, 2x^3–2x^2=10x^2

   Or, 2x^3–10x^2–2x^2=0

   Or,2x^3–12x^2=0

   Or, 2x^2(x-6)=0

   Either 2x^2=0

   Or, x=0

   /OR x-6=0

   Or,x=6

   But x can not be 0

   Therefore x=6

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