Two workers A and B working together completed a job in 5 days. If A worked twice as
efficiently as he actually did and B wor

1 thought on “Two workers A and B working together completed a job in 5 days. If A worked twice as<br />efficiently as he actually did and B wor”

1. • 6.25 days.

   • Let’s use x to represent the amount of work needed to complete the job.

   • ’a’ is the amount of work done by worker A in one day.

   • ’b’ is the amount of work done by worker B in one day.

   • By the wording of the question, we know that:

   • 5a + 5b = x

   • (3a) 2 + (3b)/3 = x

   • Since both equations are equal to the same value (x), we can set them equal to each other, and solve for b in terms of a.

   • 5a + 5b = (3a)2 + (3b)/3

   • 5a + 5b = 6a + b (simplify the right side)

   • 4b = a (subtract 5a and b from each side)

   • b = a/4

   • We now know that A works 4 times faster than B.

   • By inserting our value for b (in terms of a) into the very first equation, we get:

   • 5a + 5b = x

   • 5a + 5(a/4) = x

   • (5 + 5/4)a = x

   • 6.25a = x

   • So worker A can do the same job alone in 6.25 days.

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