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The numerator of a fraction is smaller than its denominator by 1. I

By Julia

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The numerator of a fraction is smaller than its denominator by 1. If the numerator is
increased by 4 and the denominator is doubled the number becomes 1. Find the fraction.​

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Julia

Differentiat Y=//(x²-1)
[tex] differentiat y = \sqrt( {x }^{2} – 1)[/tex]
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Initial velocity of an object is 4 kmh-1 and final velocity is 6 kmh-1, then find out Average velocity of the object?​

2 thoughts on “<br />[tex] \\ \\ \\ \\ \\ \\ \\ \\ \\ \\ [/tex]<br />The numerator of a fraction is smaller than its denominator by 1. I”

  1. question

    The numerator of a fraction is smaller than its denominator by 1. If the numerator is

    The numerator of a fraction is smaller than its denominator by 1. If the numerator isincreased by 4 and the denominator is doubled the nu

    mber becomes 1. Find the fraction.

    ANSWER

    Let numerator be x – 1

    Let numerator be x – 1Denominator be x

    Let numerator be x – 1Denominator be xAccording to the Question:-

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹ 2x

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹ 2xx−1+4

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹ 2xx−1+4

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹ 2xx−1+4

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹ 2xx−1+4 \tt\implies \: x + 3 = 2x⟹x+3=2x

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹ 2xx−1+4 \tt\implies \: x + 3 = 2x⟹x+3=2x\tt\implies \: 2x – x = 3⟹2x−x=3

    Let numerator be x – 1Denominator be xAccording to the Question:-\tt\implies \: \dfrac { x – 1 + 4 } { 2x } ⟹ 2xx−1+4 \tt\implies \: x + 3 = 2x⟹x+3=2x\tt\implies \: 2x – x = 3⟹2x−x=3\tt\implies \: x = 3⟹x=3

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  2. [tex]\huge\pink{\mid{\fbox{\tt{Answer࿐}}\mid}}[/tex]

    ∣

    To Find:-

    Find the fraction.

    Solution:-

    Here ,

    • Let numerator be x – 1
    • Denominator be x
    • According to the Question:-

    [tex]\tt\implies \: \dfrac { x – 1 + 4 } { 2x } [/tex]

    [tex]\tt\implies \: x + 3 = 2x[/tex]

    [tex]\tt\implies \: 2x – x = 3[/tex]

    [tex]\tt\implies \: x = 3[/tex]

    Hence ,

    • Denominator is 3
    • Numerator is x – 1 = 2
    Reply

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