The 17th term of an AP exceeds its 10th term by 7. Find the common difference​

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1. Answer:

   a7-a10 = 7

   a+(7-1)d – [a+(10-1)d] = 7

   a+ 6d– a – 9d = 7

   6d – 9d = 7

   -3d = 7

   d = 7/-3

   d = -7/3

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