18. A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at randomfrom the box, find the probability that it bears (i) a two-digit number (ii) a perfectsquare number (iii) a number divisible by 5. About the author Mary
answer – P ( 2-digit no. ) = 81/90 = 67/30 2) P ( a perfect square ) = 9/90 = 1/10 3) P ( number divisible by 5 ) = 18/90 = 1/5 Reply
[tex]\huge{\underline{\underline{\bf{\purple{answer}}}}}[/tex] 1) P ( 2-digit no. ) = 81/90 = 67/30 2) P ( a perfect square ) = 9/90 = 1/10 3) P ( number divisible by 5 ) = 18/90 = 1/5 Reply
answer –
2) P ( a perfect square ) = 9/90 = 1/10
3) P ( number divisible by 5 ) = 18/90 = 1/5
[tex]\huge{\underline{\underline{\bf{\purple{answer}}}}}[/tex]
1) P ( 2-digit no. ) = 81/90 = 67/30
2) P ( a perfect square ) = 9/90 = 1/10
3) P ( number divisible by 5 ) = 18/90 = 1/5