The focal length of the eye lens in Huygen’seye-piece is 3 cm. Calculate i) focal lengthof field lens, ii) distance between thelenses.O 3 cm & 6 cm resp.O 9 cm & 3 cm resp.O 6 cm & 9 cm resp.O 9 cm & 6 cm resp. About the author Ava
Effective focal length, F=3cm For Huygens eyepiece, if focal length of field lens is f, then effective focal length F= 2 f => f=2F=6cm=0.06m Focal power of field lens = 1f = 16.7D O 3 cm & 6 cm resp is the answerr. Reply
Answer: 0 3 is piece of eye 09 cm is calculated by 3 cm Step-by-step explanation: 09 is distance between the lenses Reply
Effective focal length, F=3cm
For Huygens eyepiece, if focal length of field lens is f, then effective focal length F= 2
f
=> f=2F=6cm=0.06m
Focal power of field lens =
1f
= 16.7D
O 3 cm & 6 cm resp is the answerr.
Answer:
0 3 is piece of eye 09 cm is calculated by 3 cm
Step-by-step explanation:
09 is distance between the lenses