The mid point of a line segment is (6,_1) if one end point is (2,6) .Find the second end point​

2 thoughts on “The mid point of a line segment is (6,_1) if one end point is (2,6) .Find the second end point​”

1. Answer:

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   Step-by-step explanation:

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2. Step-by-step explanation:

   Given:–

   The mid point of a line segment is (6,_1) and one end point is (2,6) .

   To find:–

   Find the second end point?

   Solution:–

   Let the second end point of a line be (x2, y2)

   One end point = (2,6)

   Let (x1, y1)=(2,6)=>x1=2 and y2=6

   The mid point of a linesegment joining the points (x1, y1) and (x2, y2) is denoted by M(x,y) and defined by

   [(x1+x2)/2 , (y1+y2)/2]

   =>M(x,y)=[(2+x2)/2 , (6+y2)/2]

   According to the given problem

   Mid point of the given linesegment = (6,-1)

   =>[(2+x2)/2 , (6+y2)/2] = (6,-1)

   On comparing both sides then

   =>(2+x2)/2=6 and (6+y2)/2=-1

   =>2+x2=6×2 and 6+y2=-1×2

   =>2+x2=12 and 6+y2=-2

   =>x2=12-2 and y2=-2-6

   =>x2=10 and y2=-8

   (x2, y2)=(10,-8)

   The required point =(10,-8)

   Answer:–

   The second end point of the given line segment is (10,-8)

   Check:–

   We have (x1, y1)=(2,6)=>x1=2 and y2=6

   (x2, y2)=(10,-8)=>x2=10 and y2=-8

   Mid Point = [(x1+x2)/2 , (y1+y2)/2]

   =>M(x,y)=[(2+10)/2 ,(6-8)/2]

   =>M(x,y)=(12/2,-2/2)

   M(x,y)=(6,-1)

   Verified the given relation.

   Used formula:–

   The mid point of a linesegment joining the points (x1, y1) and (x2, y2) is denoted by M(x,y) and defined by

   [(x1+x2)/2 , (y1+y2)/2]

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