A wire 60m long is bent to a right angled triangle of hypotenuse 26 cm.complete the length of other two sides About the author Amelia
Answer: hello ans is 10 and 24 Step-by-step explanation: Wire length = 60 cm right triangle is formed perimeter = 60 cm hypotenuse = 26 so sum of legs = 60 -26 = 34cm let one leg be x other leg = 34-x (34-x)^2+x^2= 26^2 1156-68x+x^2= 676 2x^2-68x+1156-676=0 2x^2-68x+480=0 /2 x^2-34x+240=0 x^2-24x-10x+240=0 x(x-24)-10(x-24)=0 (x-24)(x-10)=0 The legs are 24 & 10 cm manasilayanu vijarikkunu hope it helps u pls mark as brainlist Reply
Answer:
hello
ans is 10 and 24
Step-by-step explanation:
Wire length = 60 cm
right triangle is formed
perimeter = 60 cm
hypotenuse = 26
so sum of legs = 60 -26 = 34cm
let one leg be x
other leg = 34-x
(34-x)^2+x^2= 26^2
1156-68x+x^2= 676
2x^2-68x+1156-676=0
2x^2-68x+480=0
/2
x^2-34x+240=0
x^2-24x-10x+240=0
x(x-24)-10(x-24)=0
(x-24)(x-10)=0
The legs are 24 & 10 cm
manasilayanu vijarikkunu
hope it helps u
pls mark as brainlist