3cm3. In the figure the perimeter of triangle ABC is6cmA) 11 cmB) 15 cmC) 22 cmD) 30cmP2cm B About the author Camila
By the theorem of length of tangents from an external point to a circle, measure of PA = PC Therefore, PC = PA = 4 cm Now PR = 9 cm and PR = PC + CR Therefore, 9 = 4 + CR CR = 9 – 4 = 5 cm From the theorem of tangents again, CR = BR = 5 cm and BQ = AQ = 6 cm Now we know the length of PR = 9 cm length o PQ = PA + AQ = 4 + 6 = 10 cm and length of QR = QB + BR = 6 + 5 = 11 cm Perimeter of ΔPQR = PQ + QR + PR = 10 + 11 + 9 = 30 cm Therefore, perimeter of ΔPQR is 30 cm. Reply
Answer:
30 is the answer for this questions
By the theorem of length of tangents from an external point to a circle,
measure of PA = PC
Therefore, PC = PA = 4 cm
Now PR = 9 cm
and PR = PC + CR
Therefore, 9 = 4 + CR
CR = 9 – 4 = 5 cm
From the theorem of tangents again,
CR = BR = 5 cm
and BQ = AQ = 6 cm
Now we know the length of PR = 9 cm
length o PQ = PA + AQ = 4 + 6 = 10 cm
and length of QR = QB + BR = 6 + 5 = 11 cm
Perimeter of ΔPQR = PQ + QR + PR
= 10 + 11 + 9
= 30 cm
Therefore, perimeter of ΔPQR is 30 cm.