To find : The distance between the origin [tex]\sf{\pmb{(0,~0)}}[/tex] and [tex]\sf{\pmb{(-6,~8)}}[/tex] Solution : Distance formula for a point on origin : [tex] \sf \underline{ \boxed{ \sf{ \pmb{ \sqrt{x^{2} + y^{2} } }}}}[/tex] Given : x = –6 y = 8 [tex]\sf\implies{{\sqrt{x^{2}+y^{2}}}}[/tex] [tex]\sf\implies{{\sqrt{(-6)^{2}+(8)^{2}}}}[/tex] [tex]\sf\implies{{\sqrt{36+64}}}[/tex] [tex]\sf\implies{{\sqrt{100}}}[/tex] [tex]\sf{~~~~~{\blue{ \bigstar {\underline{\boxed{\sf{\pmb{10~units}}}}}}}}[/tex] ∴ Required answer : Distance = [tex]\sf{{\blue{\underline{\underline{\sf{\pmb{10~units}}}}}}}[/tex] Reply
the distance between thought the origin is 18
To find :
Solution :
Given :
[tex]\sf\implies{{\sqrt{x^{2}+y^{2}}}}[/tex]
[tex]\sf\implies{{\sqrt{(-6)^{2}+(8)^{2}}}}[/tex]
[tex]\sf\implies{{\sqrt{36+64}}}[/tex]
[tex]\sf\implies{{\sqrt{100}}}[/tex]
[tex]\sf{~~~~~{\blue{ \bigstar {\underline{\boxed{\sf{\pmb{10~units}}}}}}}}[/tex]
∴ Required answer :