Answer: [tex]\bf\blue{Question}[/tex] Solve the following equation :- 2x – 3 = -5 [tex]\bf\blue{To\:find}[/tex] We have to find x in the given expression. [tex]\bf\blue{Solution}[/tex] = 2x – 3 = -5 = 2x = -5 + 3 = 2x = -2 [tex] = x = \frac{ – 2}{2} [/tex] [tex]\leadsto\sf \cancel\dfrac{-2}{2}[/tex] = -1 •°• x = -1 [tex]\bf\blue{Verification:-}[/tex] = 2x – 3 = -5 Here x = -1 = 2 × (-1) – 3 = -5 = -2 – 3 = -5 = -5 = -5 Hence Verified LHS = RHS x = –1 Note:– – & – = + + & + = + – & + = + Reply
Answer:
[tex]\bf\blue{Question}[/tex]
[tex]\bf\blue{To\:find}[/tex]
We have to find x in the given expression.
[tex]\bf\blue{Solution}[/tex]
= 2x – 3 = -5
= 2x = -5 + 3
= 2x = -2
[tex] = x = \frac{ – 2}{2} [/tex]
[tex]\leadsto\sf \cancel\dfrac{-2}{2}[/tex]
= -1
•°• x = -1
[tex]\bf\blue{Verification:-}[/tex]
= 2x – 3 = -5
Here x = -1
= 2 × (-1) – 3 = -5
= -2 – 3 = -5
= -5 = -5
Hence Verified
LHS = RHS
x = –1
Note:–
– & – = +
+ & + = +
– & + = +