in a right triangle right angled at B AC is equal to 13 cm and ab is equal to 5 cm then find sin a​

1 thought on “in a right triangle right angled at B AC is equal to 13 cm and ab is equal to 5 cm then find sin a​”

1. Answer:

   AB2+ BC2= AC2

   5 square + BC2 = 13 Square

   BC2 = 169 – 25

   BC = 12 cm

   SinA = BC/AC

   SinA = 12/13

   Step-by-step explanation:

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