Find the area of a square, the length of diagonal is 2under root2 m.​

2 thoughts on “Find the area of a square, the length of diagonal is 2under root2 m.​”

1. Answer :-

   Area of the square = 4 m²

   Given :-

   The diagonal of the square = 2√2 m

   To find :-

   Area of the square

   Solution :-

   First we have to find the side of the square. Then, we will find the area of the square by using the value of the side of the square.

   => Diagonal of a square = side × √2

   => 2√2 m = side × √2

   => [tex]\dfrac{2\sqrt{2} }{\sqrt{2} }[/tex]m = side

   => 2 m = side

   => Area of a square = (side)²

   => Area = (2 m)²

   => Area = 4 m²

   More To Know :-

   [tex]\star[/tex] Perimeter of square = 4 x side

   [tex]\star[/tex] Perimeter of rectangle = 2(Length + Breadth)

   [tex]\star[/tex] Diagonal of rectangle = [tex]\sqrt{(Length)^2 +(Breadth)^2 }[/tex]

   [tex]\star[/tex] Area of rectangle = Length × Breadth

   Reply

2. [tex]\Large{\underbrace{\sf{\purple{Required\:Answer:}}}}[/tex]

   ⛦ Given :-

   • The diagonal of the square = 2√2 m

   ⛦ To find :-

   • Area of the square

   ⛦ Solution :-

   First we have to find the side of the square. Then, we will find the area of the square by using the value of the side of the square.

   ∵ Diagonal of a square = side × √2

   ⇒ 2√2 m = side × √2

   ⇒ [tex]\dfrac{2\sqrt{2} }{\sqrt{2} }[/tex]m = side

   ⇒ 2 m = side

   ∵ Area of a square = (side)²

   ⇒ Area = (2 m)²

   ⇒ Area = 4 m²

   ⠀⠀───────────────

   Reply