If (x – a) is a multiple of x³ – ax² – 2x + 5a – 7 then find the value of “a”.

1 thought on “If (x – a) is a multiple of x³ – ax² – 2x + 5a – 7 then find the value of “a”.”

1. Step-by-step explanation:

   x^3+ax^2-2x+a+4 Must be divisible by x+a

   so,( x3+ax2−2x+a+4)/(x+a)

   =x^2–2 is quotient and (a+4)-(-2a) is remainder

   But the polynomial is divisible so the remainder should be 0

   Thus , (a+4)-(-2a)=0

   =>(a+4+2a)=0

   =>3a+4=0

   =>a=-4/3

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