The angles of a quadrilateral are (x). (x – 10), (x + 30) and (2x), find the smallestangle About the author Faith
[tex]\huge{\underline{\underline{\bf{\purple{answer}}}}}[/tex] [tex] \angle a + \angle b + \angle c + \angle d = 360 \\ \\ x + x – 10 + x + 30 + 2x = 360 \\ \\ 5x = 360 – 30 \\ \\ 5x = 330 \\ \\ x = \frac{330}{5} = 66 \\ \\ [/tex] x = 66° x – 10 = 66 – 10 = 56° x + 30 = 66 + 30 = 96° 2x = 2 × 66 = 132° SMALLEST ANGLE IS ( X – 10 ) i.e 56° ☆BE BRAINLY☆ Reply
Answer:
smallest angle be 68 degree
[tex]\huge{\underline{\underline{\bf{\purple{answer}}}}}[/tex]
[tex] \angle a + \angle b + \angle c + \angle d = 360 \\ \\ x + x – 10 + x + 30 + 2x = 360 \\ \\ 5x = 360 – 30 \\ \\ 5x = 330 \\ \\ x = \frac{330}{5} = 66 \\ \\ [/tex]
x = 66°
x – 10 = 66 – 10 = 56°
x + 30 = 66 + 30 = 96°
2x = 2 × 66 = 132°
SMALLEST ANGLE IS ( X – 10 ) i.e 56°
☆BE BRAINLY☆