if 7 sin A – 24 cosec A = 0, then what is sec A
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1. Answer:

   Step-by-step explanation:

   [tex]7 \sin A – 24 \ cos A = 0\\\\7 \sin A =24 \ cos A \\\\7\tan A =24\\[/tex]

   [tex]\tan A = \frac{24}{7} \\\\\therefore \sec A=\sqrt({1}+\tan^2A )\\\\=\sqrt{1+\frac{576}{49}} \\\\=\sqrt{\frac{49+576}{49} } \\\\=\sqrt{\frac{625}{49}}\\\\\bf \sec A= \pm \frac{25}{7}[/tex]

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