Answer: Mat104 Solutions to Taylor and Power Series … – Math (Princeton) + x5/5! − x7/7! + … Then we can easily compute that cosx2 − 1 + x4/2 = x8/4! plus higher degree terms x2(x − sinx)2 = x8/(3!3!) plus … Reply
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Mat104 Solutions to Taylor and Power Series … – Math (Princeton)
+ x5/5! − x7/7! + … Then we can easily compute that cosx2 − 1 + x4/2 = x8/4! plus higher degree terms x2(x − sinx)2 = x8/(3!3!) plus …