◆formula of binomial [tex](2x + 5)(3 + x)[/tex] [tex] \\ \\ \\ [/tex] [tex] \large{(2x + 5)(3 + x)} \\ = (6x + 2x {}^{2} + 15 + 5x )\\ = 2x {}^{2} + 11x + 15 [/tex] [tex]=2x²+(6+5)x+15 \\ =2x²+6x+5x+15 \\ =2x(x+3)+5(x+3) \\ =(x+3)(2x+5)[/tex] Reply
◆formula of binomial
[tex](2x + 5)(3 + x)[/tex]
[tex] \\ \\ \\ [/tex]
[tex] \large{(2x + 5)(3 + x)} \\ = (6x + 2x {}^{2} + 15 + 5x )\\ = 2x {}^{2} + 11x + 15 [/tex]
[tex]=2x²+(6+5)x+15 \\ =2x²+6x+5x+15 \\ =2x(x+3)+5(x+3) \\ =(x+3)(2x+5)[/tex]