The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x. step by step explanation.​​

The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x. step by step explanation.​​

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  1. Answer:

    Question:

    The perimeter of a rectangle is 30 cm and its length is x cm. Find its area in terms of x.

    To find:

    • Area in terms of x

    Given:

    • Perimeter = 30 cm
    • L = x

    Answer :

    To find area first we should know value of with.

    So first Let’s find width by using this formula:

    [tex]\blue{\boxed { \sf \underline {Perimeter=2(Length+Width)}}}[/tex]

    Insert Value of length and perimeter.

    30 = 2(x + width)

    [tex]: \implies \sf \dfrac{30}{2} = (x + width)[/tex]

    [tex]: \implies \sf{}x + width = \dfrac{ { \cancel{30}}^{ \: 15} }{ { \cancel{2}}^{ \: 1} }[/tex]

    [tex]: \implies \sf{}x + width = 15[/tex]

    [tex]: \implies \sf{} \star \underline{\underline{ width = 15 – x}} \star[/tex]

    Now Let’s find Area by using this formula

    [tex]\blue{\boxed { \sf \underline {Area=Length \times Width }}}[/tex]

    [tex]: \implies \sf{}Area = x \times (15 – x)[/tex]

    [tex]: \implies \sf{} \star \underline{\underline{ Area = 15x – {x}^{2} \: cm {}^{2} }} \star[/tex]

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