Two cones have their base radii in ratio of 5 : 1 and the ratio of their heights as 1 : 5. Find the ratio of their volumes.

Two cones have their base radii in ratio of 5 : 1 and the ratio of their heights as 1 : 5. Find the ratio of their volumes.

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2 thoughts on “Two cones have their base radii in ratio of 5 : 1 and the ratio of their heights as 1 : 5. Find the ratio of their volumes.”

  1. Step-by-step explanation:

    Given :

    Two cones have their base radii in ratio of 5 : 1 and the ratio of their heights as 1 : 5. Find the ratio of their volumes.

    Solution :

    The ratio of height of cone 1 : 5

    The ratio of radius of cone is 5 : 1

    We know that (WKT), the Volume of the cone

    [tex]V \: = \frac{1}{3} {\pi \: r}^{2} h[/tex]

    Therefore,

    [tex] \frac{V1}{V2} = \frac{ \frac{1}{3} {\pi \: r1}^{2}h1 }{ \frac{1}{3} {\pi \: r2}^{2}h 2 } \\ \\ \frac{V1}{V2} = \frac{ {r1}^{2}h1}{ {r2}^{2}h2 } \\ \\ \frac{V1}{V2} = \frac{10 \: \times \: 1}{1 \: \times \: 5} \\ \\ \frac{V1}{V2} = \frac{2}{1} [/tex]

    Hence, the ratio of the volume of the cone is 2 : 1

    Reply
  2. The ratio of their heights is 25:64.

    Given, the radius of the bases of the cones are in the ratio 4:5

    Let us consider the radius of them to be 4x and 5x.

    We know,

    Volume of a cone is given as (1/3)Пr²h

    h is the height of the cone

    For, the cone with radius 4x and height h, volume V = (1/3)П(4x)²h = 16Пx²h/3

    For, the cone with radius 5x and height h’, volume V’ = (1/3)П(5x)²h’ = 25Пx²h’/3

    Given, V/V’ = 1/4

    ⇒[16Пx²h/3]/[25Пx²h’/3] = 1/4

    ⇒ 16h/25h’ = 1/4

    ⇒ h/h’ = 25/64

    This is the ratio of their heights.

    Reply

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