Find the value of Dx, for solving the simultaneous equations 3x + 4y = 8; x – 2y = 5 by Cramer’s rule. About the author Everleigh
[tex]\underline{\textsf{Given:}} [/tex] [tex]\mathsf{3x+4y=8}[/tex] [tex]\mathsf{x-2y=5}[/tex] [tex]\underline{\textsf{To find:}} [/tex] [tex]\textsf{Solution of the simultaneous equations by Cramer’s rule}[/tex] [tex]\underline{\textsf{Solution:}} [/tex] [tex]\begin{gathered}\mathsf{\triangle=\left|\begin{array}{cc}3&4\\1&-2\end{array}\right|}\end{gathered} [/tex] [tex]\mathsf{\triangle=-6-4=-10}[/tex] [tex]\begin{gathered}\mathsf{{\triangle}x=\left|\begin{array}{cc}8&4\\5&-2\end{array}\right|}\end{gathered}[/tex] [tex]\mathsf{{\triangle}x=-16-20=-36}[/tex] [tex]\begin{gathered}\mathsf{{\triangle}y=\left|\begin{array}{cc}3&8\\1&5\end{array}\right|}\end{gathered} [/tex] [tex]\mathsf{{\triangle}y=15-8=7}[/tex] [tex]\textsf{By Cramer’s rule}[/tex] [tex]\mathsf{x=\dfrac{{\triangle}x}{\traingle}=\dfrac{-36}{-10}=\dfrac{36}{10}}[/tex] [tex]\mathsf{y=\dfrac{{\triangle}y}{\traingle}=\dfrac{7}{-10}=\dfrac{-7}{10}}[/tex] [tex]\underline{\textsf{Answer:}} [/tex] [tex]\textsf{The solution is}[/tex] [tex]\mathsf{x=\dfrac{36}{10}\;\;\&\;\;y=\dfrac{-7}{10}}[/tex] Find more: Find x,y,z using cramers rule, if x-y+z=4, 2x+y-3z=0 and x+y+z=2 https://brainly.in/question/9052433 By Using cramer’s rule solve the given linear equations. x + y-Z=1; 8x + 3y – 6Z=1; 4x – y +3Z =1 https://brainly.in/question/13937905 Reply
[tex]\underline{\textsf{Given:}} [/tex]
[tex]\mathsf{3x+4y=8}[/tex]
[tex]\mathsf{x-2y=5}[/tex]
[tex]\underline{\textsf{To find:}} [/tex]
[tex]\textsf{Solution of the simultaneous equations by Cramer’s rule}[/tex]
[tex]\underline{\textsf{Solution:}} [/tex]
[tex]\begin{gathered}\mathsf{\triangle=\left|\begin{array}{cc}3&4\\1&-2\end{array}\right|}\end{gathered} [/tex]
[tex]\mathsf{\triangle=-6-4=-10}[/tex]
[tex]\begin{gathered}\mathsf{{\triangle}x=\left|\begin{array}{cc}8&4\\5&-2\end{array}\right|}\end{gathered}[/tex]
[tex]\mathsf{{\triangle}x=-16-20=-36}[/tex]
[tex]\begin{gathered}\mathsf{{\triangle}y=\left|\begin{array}{cc}3&8\\1&5\end{array}\right|}\end{gathered} [/tex]
[tex]\mathsf{{\triangle}y=15-8=7}[/tex]
[tex]\textsf{By Cramer’s rule}[/tex]
[tex]\mathsf{x=\dfrac{{\triangle}x}{\traingle}=\dfrac{-36}{-10}=\dfrac{36}{10}}[/tex]
[tex]\mathsf{y=\dfrac{{\triangle}y}{\traingle}=\dfrac{7}{-10}=\dfrac{-7}{10}}[/tex]
[tex]\underline{\textsf{Answer:}} [/tex]
[tex]\textsf{The solution is}[/tex]
[tex]\mathsf{x=\dfrac{36}{10}\;\;\&\;\;y=\dfrac{-7}{10}}[/tex]
Find more:
Find x,y,z using cramers rule, if x-y+z=4, 2x+y-3z=0 and x+y+z=2
https://brainly.in/question/9052433
By Using cramer’s rule solve the given linear equations.
x + y-Z=1; 8x + 3y – 6Z=1; 4x – y +3Z =1
https://brainly.in/question/13937905