Check whether (p+1) is a factor of (p100
[tex] {p}^{?101} [/tex]
– 1) and (p – 1).​

2 thoughts on “Check whether (p+1) is a factor of (p100<br />[tex] {p}^{?101} [/tex]<br /> – 1) and (p – 1).​”

1. f(p) = p^100-1

   g(p) = p^101-1

   Check (p+1) if

   (p+1) is a factor of f & g function.

   f ( – 1 ) = ( – 1 ) ^ 100 – 1

   = 1 – 1

   = 0

   g ( – 1) = ( – 1 ) ^101-1

   = -1-1

   = -2

   Hence (p+1) is a factor of f function but not g function

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2. Answer:

   1p

   Step-by-step explanation:

   (-1)+(p-1)

   =1p jigcvhiuhghnjiiiggvccggg

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