Given we have given first term (a) = 6 common difference (d) = 3 To Find We have to find 27th term of an ap [tex]\sf\huge\bold{\underline{\underline{{Solution}}}}[/tex] Formula used here : aₙ= a+(n-1)d 27th term can be written as a₂₇= a+(27-1)d a₂₇= a+26d Now,put the values : a= 6 & d = 3 a₂₇= a+26d a₂₇= 6+26(3) a₂₇= 6+78 a₂₇= 84 hence ,27th term is 84 Extra information=> [tex]\:\:\:\:\:\:[/tex]If a,a₂,a₃,a₄,are in ap then find sum sₙ=n/2(2a+(n-1)d [tex]\:\:\:\:\:\:[/tex]If a,a₂,a₃,a₄,are in ap then find the common difference d= second term(a₂) -first term(a) Reply
Answer:
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Given
we have given first term (a) = 6
common difference (d) = 3
To Find
We have to find 27th term of an ap
[tex]\sf\huge\bold{\underline{\underline{{Solution}}}}[/tex]
Formula used here :
aₙ= a+(n-1)d
27th term can be written as
a₂₇= a+(27-1)d
a₂₇= a+26d
Now,put the values :
a= 6 & d = 3
a₂₇= a+26d
a₂₇= 6+26(3)
a₂₇= 6+78
a₂₇= 84
hence ,27th term is 84
Extra information=>
[tex]\:\:\:\:\:\:[/tex]If a,a₂,a₃,a₄,are in ap
then find sum
sₙ=n/2(2a+(n-1)d
[tex]\:\:\:\:\:\:[/tex]If a,a₂,a₃,a₄,are in ap
then find the common difference
d= second term(a₂) -first term(a)