a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculate work (cas 60=1/2​

2 thoughts on “a force 10N acts on a block ob mass 10kg at an angle of 60 displaces it 5meter calculate work (cas 60=1/2​”

1. [tex]\huge\mathcal{\fcolorbox{aqual}{red}{\fcolorbox{aqual}{orange}{Answer}}}[/tex]

   Work done in fruit case =F.S.cosθ

   =10×2×cos60

   =10J

   Work done in second case is same as 10J=FScosθ

   ⇒F×2×cos30=10

   F= 10/√3N

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2. Answer:

   ☯︎ᴡᴏʀᴋ ᴅᴏɴᴇ= 25 ᴊ

   sᴇᴇ ᴛʜᴇ ᴀᴛᴛᴀᴄʜᴍᴇɴᴛ ᴘɪᴄ

   Step-by-step explanation:

   sᴏʀʀʏ ғᴏʀ ʟᴀᴛᴇ ᴀɴsᴡᴇʀ

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