[tex]\underbrace \text{Answer:}[/tex] Let the increased quality be x. [tex] \therefore \: \frac{ \text{x}}{40} = \frac{5}{8} [/tex] [tex] \implies \: \text{8x} = 40 \times 5[/tex] [tex] \implies \: \text{x} = \frac{ \cancel{40} \times 5}{ \cancel8} [/tex] [tex] \implies \: \bf\red{{x} = 25}[/tex] ⛬ The increased quality is 25. Reply
[tex]\underbrace \text{Answer:}[/tex]
Let the increased quality be x.
[tex] \therefore \: \frac{ \text{x}}{40} = \frac{5}{8} [/tex]
[tex] \implies \: \text{8x} = 40 \times 5[/tex]
[tex] \implies \: \text{x} = \frac{ \cancel{40} \times 5}{ \cancel8} [/tex]
[tex] \implies \: \bf\red{{x} = 25}[/tex]
⛬ The increased quality is 25.