The area of rectangle yard is 91 m². If the length of the yard is 52/3 m, find its breadth. About the author Aaliyah
Given : The area of rectangle yard is 91 m². If the length of the yard is 52/3 m . Exigency To Find : Breadth of Rectangle yard . ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ ❍ Let’s Consider the Breadth of Rectangle yard be x m . [tex]\dag\:\:\frak{\underline { As ,\:We\:know\:that\::}}\\\\[/tex] [tex]\dag\:\:\boxed {\sf{ Area _{(Rectangle)} = \bigg( l \times b\bigg) }}\\[/tex] Where, l is the Length of Rectangle yard & b is the Breadth of Rectangle yard & we have given with the area of Rectangle yard is 91 m ² . ⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}\\[/tex] [tex]\qquad:\implies \sf { 91 = \dfrac{52}{3} \times x }\\[/tex] [tex]\qquad:\implies \sf { \dfrac{91\times 3 }{52} = x }\\[/tex] [tex]\qquad:\implies \sf { \cancel {\dfrac{273 }{52}} = x }\\[/tex] [tex]\qquad:\implies \bf { 5.25 m= x }\\[/tex] Therefore, ⠀⠀⠀⠀⠀[tex]\therefore {\underline{ \mathrm { Breadth \:of\:Rectangle \:is\:\bf{5.25\: m}}}}\\[/tex] ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ V E R I F I C A T I O N : [tex]\dag\:\:\frak{\underline { As ,\:We\:know\:that\::}}\\\\[/tex] [tex]\dag\:\:\boxed {\sf{ Area _{(Rectangle)} = \bigg( l \times b\bigg) }}\\[/tex] Where, l is the Length of Rectangle yard & b is the Breadth of Rectangle yard & we have given with the area of Rectangle yard is 91 m ² . ⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}\\[/tex] [tex]\qquad:\implies \sf { 91 = \dfrac{52}{3} \times 5.25 }\\[/tex] [tex]\qquad:\implies \sf { 91 = \dfrac{273}{3} }\\[/tex] [tex]\qquad:\implies \sf { 91 = \cancel {\dfrac{273}{3}} }\\[/tex] [tex]\qquad:\implies \bf { 91m^2 = 91m^2 }\\[/tex] ⠀⠀⠀⠀⠀[tex]\therefore {\underline {\bf{ Hence, \:Verified \:}}}\\\\\\[/tex] ⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀ Reply
area ÷ length .hope it will help you
Given : The area of rectangle yard is 91 m². If the length of the yard is 52/3 m .
Exigency To Find : Breadth of Rectangle yard .
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
❍ Let’s Consider the Breadth of Rectangle yard be x m .
[tex]\dag\:\:\frak{\underline { As ,\:We\:know\:that\::}}\\\\[/tex]
[tex]\dag\:\:\boxed {\sf{ Area _{(Rectangle)} = \bigg( l \times b\bigg) }}\\[/tex]
Where,
⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}\\[/tex]
[tex]\qquad:\implies \sf { 91 = \dfrac{52}{3} \times x }\\[/tex]
[tex]\qquad:\implies \sf { \dfrac{91\times 3 }{52} = x }\\[/tex]
[tex]\qquad:\implies \sf { \cancel {\dfrac{273 }{52}} = x }\\[/tex]
[tex]\qquad:\implies \bf { 5.25 m= x }\\[/tex]
Therefore,
⠀⠀⠀⠀⠀[tex]\therefore {\underline{ \mathrm { Breadth \:of\:Rectangle \:is\:\bf{5.25\: m}}}}\\[/tex]
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀
V E R I F I C A T I O N :
[tex]\dag\:\:\frak{\underline { As ,\:We\:know\:that\::}}\\\\[/tex]
[tex]\dag\:\:\boxed {\sf{ Area _{(Rectangle)} = \bigg( l \times b\bigg) }}\\[/tex]
Where,
⠀⠀⠀⠀⠀⠀[tex]\underline {\frak{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}\\[/tex]
[tex]\qquad:\implies \sf { 91 = \dfrac{52}{3} \times 5.25 }\\[/tex]
[tex]\qquad:\implies \sf { 91 = \dfrac{273}{3} }\\[/tex]
[tex]\qquad:\implies \sf { 91 = \cancel {\dfrac{273}{3}} }\\[/tex]
[tex]\qquad:\implies \bf { 91m^2 = 91m^2 }\\[/tex]
⠀⠀⠀⠀⠀[tex]\therefore {\underline {\bf{ Hence, \:Verified \:}}}\\\\\\[/tex]
⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀