find the number of sides of regular polygon each of whose exterior angle is 45° About the author Sarah
Answer: Sum of exterior angle of any polygon is 360o. As each exterior angle is 45o, number of angles or sides of the polygon is 360o45o=8. Further as each exterior angle is 45o, each interior angle is 180o−45o=135o. As there are 8 interior angles each 135o the sum of the interior angles of the polygon is 135o×8=1080o Reply
Answer:
Sum of exterior angle of any polygon is 360o.
As each exterior angle is 45o, number of angles or sides of the polygon is 360o45o=8.
Further as each exterior angle is 45o, each interior angle is 180o−45o=135o.
As there are 8 interior angles each 135o
the sum of the interior angles of the polygon is 135o×8=1080o